Mg(OH)2 + 2HCl = MgCl2 + 2H2O if 33.5g of Mg(OH)2 react, what mass of H2O could be produced
To find the mass of H2O produced, we first need to determine the balanced equation and the molar masses of the compounds involved.
The balanced chemical equation is:
Mg(OH)2 + 2HCl → MgCl2 + 2H2O
The molar masses are:
Mg(OH)2: 58.33 g/mol
HCl: 36.46 g/mol
MgCl2: 95.21 g/mol
H2O: 18.02 g/mol
Now, let's calculate the number of moles of Mg(OH)2:
moles of Mg(OH)2 = mass / molar mass
moles of Mg(OH)2 = 33.5 g / 58.33 g/mol
moles of Mg(OH)2 = 0.575 mol
According to the balanced equation, for every 1 mole of Mg(OH)2, 2 moles of H2O are produced. Therefore, the number of moles of H2O produced is twice the number of moles of Mg(OH)2:
moles of H2O = 2 * moles of Mg(OH)2
moles of H2O = 2 * 0.575 mol
moles of H2O = 1.15 mol
Finally, to find the mass of H2O produced, we multiply the number of moles of H2O by its molar mass:
mass of H2O = moles of H2O * molar mass of H2O
mass of H2O = 1.15 mol * 18.02 g/mol
mass of H2O = 20.73 g
Therefore, the mass of H2O that could be produced is approximately 20.73 grams.
To find the mass of water (H2O) that could be produced in the reaction, we need to calculate the molar mass of Mg(OH)2 and use stoichiometry to determine the mole ratio between Mg(OH)2 and H2O.
1. Calculate the molar mass of Mg(OH)2:
- Atomic mass of Mg = 24.31 g/mol
- Atomic mass of O = 16.00 g/mol
- Atomic mass of H = 1.01 g/mol
Molar mass of Mg(OH)2 = (24.31 g/mol) + 2 * [(1.01 g/mol) + (16.00 g/mol)]
= 58.33 g/mol
2. Determine the mole ratio:
From the balanced equation: Mg(OH)2 + 2HCl = MgCl2 + 2H2O
We can see that 1 mole of Mg(OH)2 produces 2 moles of H2O.
3. Convert mass of Mg(OH)2 to moles:
Given: Mass of Mg(OH)2 = 33.5 g
Moles of Mg(OH)2 = Mass / Molar mass
= 33.5 g / 58.33 g/mol
≈ 0.575 moles
4. Calculate moles of H2O:
Since the mole ratio between Mg(OH)2 and H2O is 1:2,
Moles of H2O = Moles of Mg(OH)2 * (2 moles H2O / 1 mole Mg(OH)2)
= 0.575 moles * 2
= 1.15 moles
5. Convert moles of H2O to mass:
Molar mass of H2O = (2 * 1.01 g/mol) + 16.00 g/mol
= 18.02 g/mol
Mass of H2O = Moles * Molar mass
= 1.15 moles * 18.02 g/mol
≈ 20.72 g
Therefore, the mass of water (H2O) that could be produced is approximately 20.72 grams.
33.5 g Mg(OH)2 is how many moles? mols = grams/molar mass.
Look at the equation. One mole Mg(OH)2 produces how many moles H2O? Is that two? Then grams H2O = molx molar mass.