If (x – 3) divides evenly into x^3 – x^2 – kx + k, find k. (2 marks)
x^3 – x^2 – kx + k = x^2(x-1) - k(x-1)
= (x-1)(x^2-k)
If k = 9, x-3 is an even factor of that, and the quotient is
(x-1)(x+3)
The answer is k=9
= (x-1)(x^2-k)
If k = 9, x-3 is an even factor of that, and the quotient is
(x-1)(x+3)
The answer is k=9