# algebra2

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(4/y^2-1/y^3)/(2/y+3/y^2)

Simplify. Leave answers in factored and reduced form. Put () around the polynomials on numerator and denominator.

• algebra2 -

4/y^2 - 1/y^3 = (4y-1)/y^3
2/y + 3/y^2 = (2y+3)/y^2

(4y-1)/y^3 / (2y+3)/y^2 = (4y-1)/y^3 * y^2/(2y+3)
= (4y-1)/[y(2y+3)]

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