algebra2
posted by Nancy .
(4/y^21/y^3)/(2/y+3/y^2)
Simplify. Leave answers in factored and reduced form. Put () around the polynomials on numerator and denominator.

4/y^2  1/y^3 = (4y1)/y^3
2/y + 3/y^2 = (2y+3)/y^2
(4y1)/y^3 / (2y+3)/y^2 = (4y1)/y^3 * y^2/(2y+3)
= (4y1)/[y(2y+3)]