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physics

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when a force (5*10^-4) is applied on a spring then it get expand by 5*10^-2.a small mass(0.01kg) is hanged at bottm end.after coming in equilibrium a force [f(t)=20cos(wt)] is applied at the top end for oscillation.what is the distance of small(0.01) from equilibrium position?what is angular frequency at resonancy?

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