posted by Ash .
A 25.00 mL sample of a clear saturated solution of PbI2 requires 14.3 mL of a certain AgNO3(aq) for its titration.
I^-(from satd PbI2)+ Ag^+(from AgNO3)= AgI(s)
So, this is where I am.
using the Ksp equation for PbI2:
solving for x gives me 0.00121
Giving the concentration for I = 0.00242mol/L
Times this by 25ml gives me moles...
This is where I'm stuck