College Physics

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A 42-kg girl is bouncing on a trampoline. During a certain interval after leaving the surface of the trampoline, her kinetic energy decreases to 220 J from 460 J. How high does she rise during this interval? Neglect air resistance.

Just wondering how to solve this.

  • College Physics -

    The kinetic energy decrease (240 J) equals her potential energy increase: (M*g*deltaY)

    Delta Y is her increase in elevation during that time, which is
    240J/(M*g) = 0.583 m

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