posted by Angela .
A 42-kg girl is bouncing on a trampoline. During a certain interval after leaving the surface of the trampoline, her kinetic energy decreases to 220 J from 460 J. How high does she rise during this interval? Neglect air resistance.
Just wondering how to solve this.
College Physics -
The kinetic energy decrease (240 J) equals her potential energy increase: (M*g*deltaY)
Delta Y is her increase in elevation during that time, which is
240J/(M*g) = 0.583 m