Algebra 1

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solve if x=student price and y =adult price and 2y + 5x=77 and 2y + 7x=95 what are the price for admission for both adult and child

  • Algebra 1 -

    if i have 550 students and there are 144 more boys than girls how many girls are in class

  • Algebra 1 -

    Connie, I answered this question for you on Tuesday
    http://www.jiskha.com/display.cgi?id=1331674038

  • Algebra 1 -

    REINY, Thank you for your answer and the answer is obviously correct when you go back and do the multiplying ......however , I do not just want the answer, I desperately wish to understand from start to finish how you got the answer. I am sorry if I seem stupid, really , but how did you get 2x = 18 , x=9 where did the 18 come from? I am so confused. Thanks for your help!!!! connie

  • Algebra 1 -

    I thought I showed every step in the solution ....

    line them up above each other:
    2y + 7x = 95
    2y + 5x = 77
    now subtract them to get
    0 + 2x = 18

    (2y-2y=0 , 7x-5x = 2x, 95-77 = 18)

    so 2x = 18
    divide both sides by 2
    2x/2 = 18/2
    x = 9

    sub that back into one of the original equations
    2y + 5(9) = 77
    2y + 45 = 77
    subtract 45 from both sides
    2y + 45 - 45 = 77 - 45
    2y = 32
    divide by 2
    y = 16


    so x = 9 and y = 16

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