A chemist mixes aqueous sodium bromide and aqueous lead (II) nitrate. Predict the product(s) of the reaction.
Pb^2+(aq) + 2Br^-(aq) ==> PbBr2(s)
To predict the products of a chemical reaction, we need to look at the reactants and determine the possible combinations of their elements. In this case, we have aqueous sodium bromide (NaBr) and aqueous lead (II) nitrate (Pb(NO3)2).
First, let's break down the reactants into their constituent ions. Aqueous sodium bromide dissociates into sodium ions (Na+) and bromide ions (Br-), while aqueous lead (II) nitrate dissociates into lead (II) ions (Pb2+) and nitrate ions (NO3-).
So, when we mix these reactants, we can predict that the sodium ions will combine with the nitrate ions and the lead (II) ions will combine with the bromide ions.
Therefore, the products of the reaction will be sodium nitrate (NaNO3) and lead (II) bromide (PbBr2).
The balanced equation for the reaction can be written as:
2 NaBr + Pb(NO3)2 -> 2 NaNO3 + PbBr2
Note that the subscripts in the chemical formula represent the number of atoms of each element in the compound, while coefficients represent the number of molecules or formula units.