Chemistry(Urgent, please respond, thanks!!)
posted by Hannah .
1) For the reaction system, 2 SO2(g) + O2(g) = 2 SO3(g), Kc has
a value of 4.62 at 450.0 K (Kelvin). A system, at equilibrium has the following concentrations:
(SO3) = 0.254 M; (O2) = 0.00855 M. What is the equilibrium concentration of SO2?
Is set this up as 4.62=(SO3)^2 / (SO2)^2 (O2)
4.62=(0.254)^2 / 0.00855(x^2)
4.62=0.064516/0.00855(x^2)
I am just having trouble doing the math now. I am not sure what to do.

x= sqrt (.064516/(.00855*4.62))
Put this in your google search window:
sqrt(.064516/(.00855*4.62)) 
Thank you!!

0.500