# chemistry

posted by student

A certain first order reaction has a rate constant of 3.75x10^-2 s^-1 at 25.0C. What is the value of k at 70.0C when the activation energy is 135 kj/mol?
Would I use the formula K=Ae ^-Ea/RT even though I have two temperatures?

1. DrBob222

I would use ln(k2/k1) = Ea/R(1/T1 - 1/T2)

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