Mr. Fleep had a new flying disk design. He made some calculations and decided if he could make a flying disk that had a perimeter exactly 4 times the diameter that it would be more aerodynamically stable than a "standard" flying disk and thus fly further. Is this design possible? Why or why not?
I do not believe so, because in order to get the perimeter, you multiply the diameter by pi, and that would not ever give you a perimeter that is four times the diameter, because pi is 3.14
To determine whether Mr. Fleep's new flying disk design is possible, we need to understand the relationship between the perimeter and diameter of a standard flying disk.
The perimeter of a standard flying disk can be determined using the formula for the circumference of a circle: P = 2πr, where P is the perimeter and r is the radius of the disk. The diameter of the disk is twice the radius, so D = 2r.
If Mr. Fleep's design aims to have a perimeter exactly 4 times the diameter, we can express it as P = 4D.
Substituting the formula for the perimeter (P) and diameter (D) of a standard flying disk into the equation, we get:
2πr = 4(2r)
Simplifying the equation, we have:
2πr = 8r
Dividing both sides of the equation by r, we get:
2π = 8
However, this equation is not true. The value of π (pi) is approximately 3.14, which means that 2π is approximately 6.28. Since 6.28 is not equal to 8, the equation cannot hold, and therefore, Mr. Fleep's design is not possible.
In conclusion, Mr. Fleep's new flying disk design, with a perimeter exactly 4 times the diameter, is not possible due to the mathematical inconsistency it presents.