# physics

posted by .

How far (in meters) above the earth's surface will the acceleration of gravity be 27.0 % of what it is on the surface? can someone please just give me an equation to figure this out please I am lost

• physics -

As we normally think of it, the static value of gravity on, or above the surface of a spherical body is directly proportional to the mass of the body and inversely proportional to the square of the distance from the center of the body and is defined by the expression g = GM/r^2 = µ/r^2 where GM = µ = the gravitational constant of the body (G = the Universal Gravitational Constant and M = the mass of the body) and r = the distance from the center of the body to the point in question.

With the earth's mean radius of 6378km and gravitational constant GM of 3.986365m^3/sec^2, the surface gravity g = GM/6378000^2 = 9.8m/sec^2. Therefore, the height above the earth's surface where g = .27(9.8) derives from r = sqrt[(GM/.27(9.8))/1000] - 6378.

## Similar Questions

1. ### Physics

The mean radius of the Earth is R=6.38x10^6m. At what distance above the Earth's surface will the acceleration of gravity be 4.905m/s^2?
2. ### Physics

How far above the surface of the Earth does an object have to be in order for it to have the same weight as it would have on the surface of the Moon?
3. ### physics

1. The acceleration due to gravity calculated this way works well for objects near the Earth’s surface. How would you have to change the above equation if the object was 100,000 meters above the ground?

The space shuttle orbits at a distance of 335 km above the surface of the Earth. What is the gravitational force (in N) on a 1.0 kg sphere inside the space shuttle. Assume that the mass of the Earth is 5.98x1024 kg and the radius of …
5. ### physic

How far (in meters) above the earth's surface will the acceleration of gravity be 27.0 % of what it is on the surface?
6. ### Physics

A satellite is orbiting the earth just above its surface. The centripetal force making the satellite follow a circular trajectory is just its weight, so its centripetal acceleration is about 9.81 m/s2 (the acceleration due to gravity …
7. ### physics

1. The acceleration due to gravity calculated this way works well for objects near the Earth’s surface. How would you have to change the above equation if the object was 100,000 meters above the ground?