Algebra 1

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Write an equation of a line that passes through (-12, -14) with slope 6.

A.y = 6x - 12
B.(y + 14) = 6(x + 12)
C.(y + 12) = 14(x + 6)

I've tried so many different ways to find this answer but can't. Please help me and please show me how you got it. I don't want you to just tell me the answer I want you to show me how to find others like this one. Thank you.

  • Algebra 1 -

    y = m x + b


    m = slope


    in tis case:

    m = 6

    x = - 12

    y = - 14



    y = 6 x + b

    - 14 = 6 * ( - 12 ) + b

    - 14 = - 72 + b

    - 14 + 72 = b

    58 = b

    b = 58



    y = m x + b

    y = 6 x + 58

  • Algebra 1 -

    y = 6 x + 58

    OR

    y + 14 = 6 x + 58 + 14

    y + 14 = 6 x + 72

    y + 14 = 6 ( x + 12 )

    Ansver B is correct


    Proof:

    y + 14 = 6 ( x + 12 )

    - 14 + 14 = 6 ( - 12 + 12 )

    0 = 6 * 0

    0 = 0

  • Algebra 1 -

    If you have a point (a,b) and the line has slope of m, then the equation is

    y-b = m(x-a)

    the equation in B) fits that pattern exactly.

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