# Algebra 1

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Write an equation of a line that passes through (-12, -14) with slope 6.

A.y = 6x - 12
B.(y + 14) = 6(x + 12)
C.(y + 12) = 14(x + 6)

I've tried so many different ways to find this answer but can't. Please help me and please show me how you got it. I don't want you to just tell me the answer I want you to show me how to find others like this one. Thank you.

• Algebra 1 -

y = m x + b

m = slope

in tis case:

m = 6

x = - 12

y = - 14

y = 6 x + b

- 14 = 6 * ( - 12 ) + b

- 14 = - 72 + b

- 14 + 72 = b

58 = b

b = 58

y = m x + b

y = 6 x + 58

• Algebra 1 -

y = 6 x + 58

OR

y + 14 = 6 x + 58 + 14

y + 14 = 6 x + 72

y + 14 = 6 ( x + 12 )

Ansver B is correct

Proof:

y + 14 = 6 ( x + 12 )

- 14 + 14 = 6 ( - 12 + 12 )

0 = 6 * 0

0 = 0

• Algebra 1 -

If you have a point (a,b) and the line has slope of m, then the equation is

y-b = m(x-a)

the equation in B) fits that pattern exactly.

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