Algebra2
posted by Lily .
How do I solve this rational exponent equation?
(2x)^1/2 = x  4
Thanks in advance ^^

Algebra2 
Pk
Square both side first
2x)^1/2^2=(x4)^2
2x=x^28x+16
subtract 2x from both sides
x^210x+16
now FOIL
(x8)(x2)
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