A 500.0 g metal block absorbs 3.25 × 103 J of heat to raise its temperature by 50.0 K. What is the substance?
Please show steps because I have several problems like this and then I can see where I am goibg wrong
specific heat= heatabsorbed/(mass*deltaT)
= 3.25E3J/(50C*.5kg)=130J/kgC=.130J/gC
Several have that heat capacity, Tungsten is amoung them
To determine the substance of the metal block, we can calculate its specific heat capacity. This value is different for each substance and can be used to identify the metal.
The formula for calculating the heat absorbed by an object is:
Q = mcΔT
Where:
Q = heat absorbed (in joules)
m = mass of the object (in kilograms)
c = specific heat capacity (in joules per kilogram per degree Celsius or joules per gram per degree Celsius)
ΔT = change in temperature (in degrees Celsius)
Let's calculate the specific heat capacity of the metal block:
Given:
Mass of the metal block (m) = 500.0 g = 0.500 kg
Heat absorbed (Q) = 3.25 × 10^3 J
Change in temperature (ΔT) = 50.0 K
Now, rearranging the formula to solve for c:
c = Q / (m * ΔT)
Substituting the given values:
c = (3.25 × 10^3 J) / (0.500 kg * 50.0 K)
c ≈ 130 J / kg * K
Now that we know the specific heat capacity of the metal block is approximately 130 J / kg * K, we can compare it to known values for different substances to determine the metal's identity.
Some common metals and their approximate specific heat capacities are:
- Aluminum: 900 J / kg * K
- Copper: 390 J / kg * K
- Iron: 450 J / kg * K
- Lead: 130 J / kg * K
- Silver: 240 J / kg * K
Based on the specific heat capacity we calculated for the metal block (approximately 130 J / kg * K), the substance is likely lead.