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h2c4h4o4 + 2naoh --> 2h2o + na2c4h4o4

as for the previous question im sorry i forgot to plug the maleic acid in the formula properly. so this ones it ^

.2213 of c4h4o4 used (maleic acid)
.1 M NaOH

1. show the equation for 1st and 2nd ionization
2. find molecular mass of maleic acid

help? How do I do this?

I have a list of V (mL) and pH values...
basically titrated 50 mL

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