alg2trig
posted by alice .
2(3y4)^(3/5)4=50

2(3y4)^(3/5) = 54
(3y4)^(3/5) = 27
3y  4 = 27^(5/3)
3y = 27^(5/3) + 4
y = (27^(5/3) + 4)/3
= (243 + 4)/3 = 247/3 or 82 1/3 
1(1/a)/1(1/a^2)

multiply top and bottom by a^2 to get
(a^2a)/(a^21)
= a(a1)/(a+1)(a1)
= a/(a+1)
or, since you seem to like reciprocals so much,
1 /(1+1/a)
:)
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