The electric field between the plates of a paper-separated (K = 3.75) capacitor is 9.01X10^4 V/m. The plates are 1.95 mm apart and the charge on each plate is 0.775 µC. I figured out that the capacitance is 4.4e-9F but I need help finding the area.
never mind. I figured out that it was 0.254m^2
To find the area of the plates of a capacitor, you can use the Capacitance formula:
C = (ε₀ * A) / d
where:
C is the capacitance (in Farads),
ε₀ is the permittivity of free space (a constant value equal to 8.85 x 10^-12 F/m),
A is the area of the plates (in square meters), and
d is the distance between the plates (in meters).
You have already found that the capacitance is 4.4 x 10^-9 F, and you know that the distance between the plates (d) is 1.95 mm, or 1.95 x 10^-3 m. Now, we can rearrange the formula to solve for the area (A):
A = (C * d) / ε₀
Substituting the known values:
A = (4.4 x 10^-9 F * 1.95 x 10^-3 m) / (8.85 x 10^-12 F/m)
Now, you need to perform the calculation:
A = (8.58 x 10^-12 m²)
Therefore, the area of the plates of the capacitor is approximately 8.58 x 10^-12 square meters.