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Pre-Calculus

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Find the maximum value, and where it occurs for eAch function.
G(x)= (square root -x^2+4x+12)

  • Pre-Calculus -

    the vertex of the parabola
    y = -x^2 + x + 12

    x^2 - x = -y + 12

    x^2 - x + 1/4 = -y+ 12.25

    (x-1/2)^2 = -1 (y-12.25)

    vertex at (1/2 , 12.25)

    there -x^2 + 4 x + 12.25 = -1/4+2+12.25
    = 14
    G = sqrt(14)

  • Pre-Calculus -

    4x sort (25−x2)

  • Pre-Calculus -

    nvm that is not correct! i was trying to ask a question

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