PreCalculus
posted by L.Bianchessi .
Find the maximum value, and where it occurs for eAch function.
G(x)= (square root x^2+4x+12)

the vertex of the parabola
y = x^2 + x + 12
x^2  x = y + 12
x^2  x + 1/4 = y+ 12.25
(x1/2)^2 = 1 (y12.25)
vertex at (1/2 , 12.25)
there x^2 + 4 x + 12.25 = 1/4+2+12.25
= 14
G = sqrt(14) 
4x sort (25−x2)

nvm that is not correct! i was trying to ask a question
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