1/[N2O] = 1/(1.75M) + (1.10E-3M^-1 S^-1)(1852s)

[N2O] = 0.383 M

I know I posted a similar question but I am having trouble with this one as well. Should I do 1/1.75 first and then add 1.10e-3 and then multiply by 1852?

P.E.M.D.A.S

So first I did multiplication (1.10e-3)(1852) and then divided 1/1.75 and then added and I cant get the answer.

1/[N2O] = 1/(1.75M) + (1.10E-3M^-1 S^-1)(1852s)

= 0.5714/M + 2.0372/M
= 2.6086/M
So, [N2O] = M/2.6086 = 0.3833M

You can't just divide by 1.75 since it's not a multiplier of the other term. Keep careful track of the units to avoid such mistakes.

To solve the equation, you can follow these steps:

Step 1: First, simplify the equation by finding the reciprocal of both sides:

1/[N2O] = 1/(1.75M) + (1.10E-3M^-1 S^-1)(1852s)

By taking the reciprocal of both sides, the equation becomes:

[N2O] = 1/(1/[N2O])

Since the reciprocal of a reciprocal is the original value, the equation simplifies to:

[N2O] = [N2O]

Step 2: Now, substitute the given value for [N2O], which is 0.383 M, into the equation:

[N2O] = 0.383 M

Therefore, the concentration of N2O is 0.383 M.