1/[N2O] = 1/(1.75M) + (1.10E-3M^-1 S^-1)(1852s)
[N2O] = 0.383 M
I know I posted a similar question but I am having trouble with this one as well. Should I do 1/1.75 first and then add 1.10e-3 and then multiply by 1852?
To solve the given equation 1/[N2O] = 1/(1.75M) + (1.10E-3M^-1 S^-1)(1852s) for [N2O], you need to follow the order of operations.
1. First, calculate 1/1.75 by dividing 1 by 1.75:
1/1.75 = 0.5714 (rounded to four decimal places)
2. Next, multiply the value obtained in step 1 by 1.10E-3 M^-1 S^-1 and 1852s.
0.5714 * (1.10E-3 M^-1 S^-1) * 1852s = 0.5714 * 0.0011 M^-1 S^-1 * 1852s
This will give you the value in M^-1 S^-1 * s.
3. Finally, add the result obtained in step 2 to step 1:
[N2O] = 0.5714 + (0.5714 * 0.0011 M^-1 S^-1 * 1852s)
Simplify the expression further, and you will get the final value of [N2O].
Note: Ensure that you correctly perform the calculations using the appropriate units and significant figures to obtain the accurate result.