Post a New Question

Math

posted by .

2x^3+3x^2-120x

to find the critical numbers I took the derivative which is 6x^2+6x-120 so divide by 6 to simplify

x^2+x-20=0

so the critical numbers will be (4,0) and (-5,0) but its wrong I don't know y?

  • Math -

    Your work looks good to me, but the critical numbers are 4 and -5, not the points you give.

    Recall the definition:

    A number a in the domain of a given function f is called a critical number of f if f '(a) = 0 or f' is undefined at x = a.

  • Math -

    Thnks :)

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question