If one started will 4.33g of copper(11) chloride , how may grams of copper could be produced?
The easy way to do it is
4.33 g CuCl2 x (atomic mass Cu/molar mass CuCl2) = ?
275.1282
Not even close.
To determine how many grams of copper can be produced from 4.33g of copper(II) chloride, we need to use stoichiometry, which is the ratio of moles between two substances in a chemical reaction.
First, let's write the balanced chemical equation for the reaction:
2CuCl2 + H2 -> 2HCl + 2Cu
From the equation, we can see that the ratio between copper(II) chloride (CuCl2) and copper (Cu) is 2:2 or 1:1.
Now, we need to convert the mass of copper(II) chloride to moles. To do this, we use the molar mass of copper(II) chloride, which is the sum of the atomic masses of copper (Cu) and chlorine (Cl).
Molar mass of CuCl2 = atomic mass of Cu + 2 * atomic mass of Cl = 63.55 g/mol + 35.45 g/mol * 2 = 134.45 g/mol
Next, we calculate the number of moles of CuCl2:
moles of CuCl2 = mass of CuCl2 / molar mass of CuCl2 = 4.33 g / 134.45 g/mol
Now, since the stoichiometry ratio between CuCl2 and Cu is 1:1, the number of moles of Cu produced will be equal to the number of moles of CuCl2. Therefore:
moles of Cu = moles of CuCl2
Finally, to determine the mass of copper produced, we multiply the moles of Cu by the molar mass of copper.
mass of Cu = moles of Cu * molar mass of Cu
Substituting the values, we get:
mass of Cu = 4.33 g / 134.45 g/mol * 63.55 g/mol
Now, calculate the final value to find the mass of copper produced.