Complete and balance the following equations
NaHCO3(s)+H+(aq)--->
CaO(s)+C(s)--->
C(s)+H2O(g)--->
CuO(s)+CO(g)--->
If possible include charges and physical state.
I THINK ITS
1) The balanced equation is NaHCO3(s) + H+(aq)= Na+(aq) + CO2(g) + H2O(aq). Remember acid + base = salt + water.
2) 2 CaO(s) + 5 C(s) = 2 CaC2(s) + CO2(g)
3)C(s)+H2O(g)=>CO(g)+H2(g
4) CuO (s) + CO (g) Cu (s) + CO2 (g)
I THINK THEY ARE RIGHT.
CHECK WITH SOMEONE ELSE IF ITS TRUE
Those look ok to me.
NaHCO3(s)+H+(aq)-->Na+(aq)+CO2(g)+H2O(l)
CaO(s)+C(s)-->CaC2(s)
C(s)+H2O(g)-->CO(g)+H2(g)
CuO(s)+CO(g)-->Cu(s)+CO2(g)
1. NaHCO3(s) + H+(aq) ---> Na+(aq) + CO2(g) + H2O(l)
Balanced equation: 2NaHCO3(s) + 2H+(aq) ---> 2Na+(aq) + 2CO2(g) + 2H2O(l)
2. CaO(s) + CO2(g) ---> CaCO3(s)
Balanced equation: CaO(s) + CO2(g) ---> CaCO3(s)
3. C(s) + H2O(g) ---> CO(g) + H2(g)
Balanced equation: C(s) + 2H2O(g) ---> CO(g) + 2H2(g)
4. CuO(s) + CO(g) ---> Cu(s) + CO2(g)
Balanced equation: CuO(s) + CO(g) ---> Cu(s) + CO2(g)
To complete and balance the equations, we need to ensure that the number of atoms on both sides of the equation is equal, and that the charges are balanced. Let's go through each equation one by one.
1. NaHCO3(s) + H+(aq) ---> Na+(aq) + H2O(l) + CO2(g)
In this equation, we balance the charges by transferring the H+ ion to the Na+, forming water (H2O) and carbon dioxide (CO2).
2. CaO(s) + C(s) ---> CaC2(s)
In this equation, we balance the equation by forming calcium carbide (CaC2) from calcium oxide (CaO) and carbon (C).
3. C(s) + H2O(g) ---> CO(g) + H2(g)
In this equation, carbon (C) reacts with water vapor (H2O) to form carbon monoxide (CO) and hydrogen gas (H2).
4. CuO(s) + CO(g) ---> Cu(s) + CO2(g)
In this equation, copper oxide (CuO) reacts with carbon monoxide (CO) to produce copper (Cu) and carbon dioxide (CO2).
Note: Physical states are indicated in parentheses. (s) denotes solid, (aq) denotes aqueous, (l) denotes liquid, and (g) denotes gas.