A CD has a mass of 17.0 g and a radius of 5.98 cm. When inserted into a player, the CD starts from rest and accelerates to an angular velocity of 19.1 rad/s in 0.744 s. Assuming the CD is a uniform solid disk, determine the net torque acting on it.

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To determine the net torque acting on the CD, we can use the rotational version of Newton's second law, which states that the net torque acting on an object is equal to the product of its moment of inertia and its angular acceleration.

1. Calculate the moment of inertia of the CD using the formula: I = (1/2) * m * r^2
where I is the moment of inertia, m is the mass of the CD, and r is the radius.

Given:
Mass of the CD (m) = 17.0 g = 0.017 kg
Radius of the CD (r) = 5.98 cm = 0.0598 m

Plugging in the values:
I = (1/2) * 0.017 kg * (0.0598 m)^2
I = 5.0698 × 10^(-5) kg·m^2

2. Calculate the angular acceleration of the CD using the formula: α = (ωf - ωi) / t
where α is the angular acceleration, ωf is the final angular velocity, ωi is the initial angular velocity, and t is the time taken.

Given:
Final angular velocity (ωf) = 19.1 rad/s
Initial angular velocity (ωi) = 0 rad/s (since the CD starts from rest)
Time taken (t) = 0.744 s

Plugging in the values:
α = (19.1 rad/s - 0 rad/s) / 0.744 s
α = 25.746 rad/s^2

3. Calculate the net torque using the formula: τ = I * α
where τ is the net torque, I is the moment of inertia, and α is the angular acceleration.

Plugging in the values:
τ = 5.0698 × 10^(-5) kg·m^2 * 25.746 rad/s^2
τ = 1.3021 × 10^(-3) N·m

Therefore, the net torque acting on the CD is 1.3021 × 10^(-3) N·m.