physics

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Calculate the hang time of a person who moves horizontally 2.00 m during a 1.23 m high jump.
Express your answer with the appropriate units

  • physics -

    The motion of jumping person is similar to projectile motion:
    H=(Vo)^2•(sinα)^2/2g
    L=(Vo)^2•(sin2α)/2g=
    =(Vo)^2•(2sinα•cosα)/2g.

    2H/L=sinα/cosα,

    tanα=2H/L=21.23/2=1.23

    α=arctan1.23=50.9°

    Vo=sqr(2gH)/ sinα=6.33 m/s.
    t=2Vo•sinα/g=1 s.

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