How do factor a binomial with cubed roots?
cos^3+sin^3/cosx+sinx = 1-sinxcosx
Are you trying to prove the identity?
You can use the following algebraic identity:
a^3+b^3=(a+b)(a^2-ab+b^2)
cos^3+sin^3/cosx+sinx = 1-sinxcosx
You can use the following algebraic identity:
a^3+b^3=(a+b)(a^2-ab+b^2)