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A flatbed truck is carrying a 2540 kg crate of heavy machinery. If the coefficient of static friction between the crate and the bed of the truck is 0.540 , what is the maximum rate (in meters/second^2) that the driver can decelerate when coming to a stop, in order to avoid crushing the cab of the truck with the crate?

  • physics -

    M*a = Max static friction force
    = M*g*0.54
    M cancels out
    a = 0.54g = 5.29 m/s^2
    (assuming the crate is not tied down)

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