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Math

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The size of a bacteria population is given by P=C*e^(kt) Where C is the initial size of the population, k is the growth rate constant and t is time in minutes.
a) If the bacteria in the population double their number every minute, what is the value of k?

I need help please!

  • Math -

    P(0)=Ce^(k*0)=C
    P(1)=Ce^(k*1)=Ce^k
    P(1)/P(0)=2=(ce^k)/C=e^k
    Take natural log
    ln(2)=ln(e^k)=k
    k=ln(2)=0.6931 approx.

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