find the value of K so that 3x^2-6x+k=0 has a double root
answer is 3. how do you find that
dont answer i figured it out
To find the value of K so that the quadratic equation 3x^2 - 6x + k = 0 has a double root, we can use the discriminant of the quadratic formula.
The quadratic formula is given by:
x = (-b ± √(b^2 - 4ac))/(2a)
For a quadratic equation to have a double root, the discriminant (b^2 - 4ac) must be equal to zero.
In the given equation, a = 3, b = -6, and c = k. Substituting these values into the formula, we get:
Discriminant = (-6)^2 - 4(3)(k)
= 36 - 12k
To find the value of K, we set the discriminant equal to zero and solve for K:
36 - 12k = 0
12k = 36
k = 36/12
k = 3
Therefore, the value of K that gives the quadratic equation 3x^2 - 6x + k = 0 a double root is K = 3.