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power supply has an open-circuit voltage of 39.0 V and an internal resistance of 2.00 Ù. It is used to charge two storage batteries connected in series, each having an emf of 5.50 V and internal resistance of 0.300 Ù. The charging current is to be 3.30 A.

  • physics -

    I=(E-(5.5+5.5)) / (2+0.3+0.3) = 3.30 A.
    (E-11) / 2.6 = 3.30.
    E-11 = 8.58.
    E = 8.58 + 11 = 19.58 Volts=Voltage
    setting required for a charging current of 3.30 amps.

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