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Chemistry

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Calculate the pH of an aqueous solution containing 3.8 10-2 M HCl, 1.0 10-2 M H2SO4, and 3.3 10-2 M HCN.

  • Chemistry -

    HCl is 100% ionized; therefore, (H^+) = (HCl)
    HCN is a weak acid
    ..........HCN ==> H^+ + CN^-
    initial.0.033......0......0
    change.....-x.......x.....x
    equil.....0.33-x...x......x

    Ka = (H^+)(CN^-)/(HCN)
    Look up Ka, substitute it and the ICE chart values and solve for x = H^+, then convert to pH.

    For H2SO4, see your other post just before this one.

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