# Chemistry

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Calculate the pH of an aqueous solution containing 3.8 10-2 M HCl, 1.0 10-2 M H2SO4, and 3.3 10-2 M HCN.

• Chemistry -

HCl is 100% ionized; therefore, (H^+) = (HCl)
HCN is a weak acid
..........HCN ==> H^+ + CN^-
initial.0.033......0......0
change.....-x.......x.....x
equil.....0.33-x...x......x

Ka = (H^+)(CN^-)/(HCN)
Look up Ka, substitute it and the ICE chart values and solve for x = H^+, then convert to pH.

For H2SO4, see your other post just before this one.

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