An electron in a cathode-ray-tube (CRT) accelerates from 20300 m/s to 3.99 × 106 m/s over 1.34 cm.
How long does the electron take to travel this distance?
(Vf^2-Vi^2)/(2(deltax)) so ((3.9910^6)^2-(20300)^2)/(2(0.0134)) which equals 5.9 x 10^14
To find the time it takes for the electron to travel the given distance, we can use the formula:
distance = initial velocity × time + (1/2) × acceleration × time^2
In this case, the distance is 1.34 cm, the initial velocity is 20300 m/s, and the final velocity is 3.99 × 10^6 m/s. It's important to note that since the problem only provides information regarding acceleration and not the actual acceleration value, we can assume that the acceleration is constant.
As the distance, initial velocity, and final velocity are given, the only variable we're trying to find is time. Hence, we can rearrange the formula to solve for time:
time = (final velocity - initial velocity) / acceleration
Plugging in the given values:
time = (3.99 × 10^6 m/s - 20300 m/s) / acceleration
Since we don't have the value for acceleration in the problem, we cannot directly calculate the time. If the problem provides additional information about the acceleration, we can substitute it into the equation and find the answer.