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calculus

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limx-0 x-sinx/xcube

  • calculus -

    I assume that the numerator is (x - sinx)

    In a Taylor series,
    x - sinx = x^3/3! - x^5/5! + ...

    Divide that by x^3

    The limit as x->0 is therefore 1/3! = 1/6

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