golf view

posted by .

Explain how the graph of sin2 theta relates to y=sin theta

  • trig -

    Do you mean
    sin^2(theta) or sin(2theta) ?

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Trig(3 all with work)

    1)Find the exact value of cos 105 by using a half-angle formula. A)sqrt 2 - sqrt 3 /2 B)-sqrt 2 - sqrt 3 /2 C)-sqrt 2 + sqrt 3 /2 D)sqrt 2 + sqrt 3 /2 cos 105 cos 105 = cos 210/2 sqrt 1 + 210/2 sqrt 1 + sqrt 3/2 /2 sqrt 2 + sqrt 3/2 …
  2. Trig(continued)

    2)Find the solution of sin2 theta = cos theta if 0 -< theta < 180 A)30 degrees and 90 degrees B)30 degrees and 150 degrees C)30 degrees, 90 degrees, 150 degrees D)0 degrees, 90 degrees, and 150 degrees sin2 theta = cos theta …
  3. Trig

    Find the exact value of sin2(theta) if cos(theta) = -sqrt 5/3 and 180 < theta < 270. A)-1/9 B)-4 sqrt 5/9 C)1/9 D)4 sqrt 5/9 B?
  4. Calculus

    I wanted to confirm that I solved these problems correctly (we had to convert the polar curves to Cartesian equations). 1.rcos(theta)=1 x=1 2.r=2*sin(theta)+2*cos(theta) r^2=2rsin(theta)+2rcos(theta) x^2+y^2=2y+2x (a little unsure …
  5. Physics

    An object is shot at 20m/s at an angle theta. The object lands 24m away. What is the angle?
  6. Algebra II

    Multiple Choice Which expression is NOT equivalent to 1?
  7. math

    knowing that 2(theta) can be written as theta + theta, find the expression for sin2(theta) and cos2(theta). Is it 2sin(theta)cos(theta)?
  8. Mathamatics

    Solve the following trigonometry identities. a) 1-cos2(theta) = sin(theta)cos(theta)/cot(theta) b) (1-cos2(theta))(1-tan2(theta))=sin2(theta)-2sin4(theta)/1-sin2(theta) *its supposed to be cos to the power of two, sin to the power …
  9. Calculous

    Evaluate sin(theta) and cosine (theta) for the angle theta The graph gives you a point of (0.6,-0.8) on the x y coordinate plane with a radius of what appears to be 1 ( unit circle ) sin (theta) = cos (theta) =
  10. Trigonometry

    Prove the following identities: 1. (tan theta - sin theta)^2 + (1-cos theta)^2 = (1-sec theta) ^2 2. (1-2cos^2 theta) / sin theta cos theta = tan theta - cot theta 3. (sin theta + cos theta ) ^2 + (sin theta - cos theta ) ^2 = 2 Thank …

More Similar Questions