Post a New Question


posted by .

How do i determine the mass of ice initially in the calorimeter when dry saturated steam is passed into 250g of a mixture of ice and water in a calorimeter of thermal capacity 45J/K when all the ice has just melted,and the mass of the content in the calorimeter has increased by 10g due to condensed steam ?

  • Physics -

    If all the ice has "just" melted, the liquid is still 0 degrees C. That is the same temperature that the ice-water mixture started out. The calorimeter also remained 0 C during the ice melting, so you can ignore its heat capacity. The 10 g of steam cooled from 100 to 0 C and released 540*10 + 100*10 = 6400 calories to the icewater. That is enough heat to just melt 6400/80 = 80 g of ice.

    80 g of ice was initially present.

    The amount of icewater initially present and the heat capacity of the calorimeter were not needed in this case.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question