For the reaction system, 2 H2O(g) + O2(g) == 2 H2O2 (g), the equilibrium concentrations are
(H2O2) = 0.120 M; (H2O) = 0.860 M; (O2) = 0.330 M.
Calculate the value of Kc for this reaction.
A. 0.423
B. 0.872
C. 0.0590
D. 1.31
E. 2.51
I did 0.120 / 0.860 X 0.330 = 4.4228 = 4.23.
Did I do this correctly?
You didn't balance the equation and you didn't make the coefficients the exponents.
To balance the equation would I add a 2 in front of the O2?
To know if it balances or not, count the atoms and see. You don't need to ask anyone. You want to put a 2 for O2?
2H2O + 2O2 ==> H2O2.
I see 4 H atoms on the left. I see 2 on the right. Equation isn't balanced.
so then 4.
2H2O + 4O2 ==> H2O2
I see 4 H atoms on the left and 2 on the right. Equation isn't balanced. Quit guessing and count the atoms. Try a value and count. It's that simple.
To calculate the value of Kc for this reaction, you need to use the equilibrium concentrations of the reactants and products. The balanced equation for the reaction is:
2 H2O(g) + O2(g) ⇌ 2 H2O2(g)
The expression for Kc is given by:
Kc = ([H2O2]^2) / ([H2O]^2 * [O2])
Given the equilibrium concentrations:
[H2O2] = 0.120 M
[H2O] = 0.860 M
[O2] = 0.330 M
Substituting these values into the expression for Kc:
Kc = (0.120^2) / (0.860^2 * 0.330) = 0.156 / 0.2413 = 0.6460
Now let's compare this value to the answer choices provided:
A. 0.423
B. 0.872
C. 0.0590
D. 1.31
E. 2.51
The calculated value of Kc is 0.6460, which does not match any of the answer choices provided. Therefore, the answer is none of the above.