ln k2/2.34 = -103,000J/8.314J/Kol[1/339K - 1/359K]
ln k2/2.34 = -2.035941063
I am not sure what to do now!!
Disregard question. I figured it out. You take the ln of -2.035 and then multiply by 2.34 to get k2.
not quite. ln(x) is not defined for x<0
if ln k2/2.34 = -2.035941063
then ln k2 - ln 2.34 = -2.035941063
ln k2 = ln 2.34 - 2.035941063
ln k2 = .850150929 - 2.035941063
ln k2 = -1.185790134
k2 = e^-1.185790134
k2 = 0.3055
To find the value of k2 in the given equation, we can start by isolating k2 on one side of the equation. Here are the steps to solve the equation:
Step 1: Multiply both sides of the equation by 2.34 to get rid of the fraction on the left side:
ln(k2/2.34) = -2.035941063 * 2.34
Step 2: Simplify the right side:
ln(k2/2.34) = -4.772651029
Step 3: Now, we need to remove the natural logarithm to solve for k2. To do this, raise both sides of the equation to the power of e (exponential function):
e^(ln(k2/2.34)) = e^(-4.772651029)
Step 4: Simplify the left side using the logarithmic property:
k2/2.34 = e^(-4.772651029)
Step 5: Multiply both sides of the equation by 2.34 to solve for k2:
k2 = 2.34 * e^(-4.772651029)
Step 6: Use the mathematical constant e (approximately equal to 2.71828) to evaluate the right side of the equation:
k2 = 2.34 * 0.008796
Step 7: Calculate the value of k2:
k2 ≈ 0.020536
Therefore, the value of k2 is approximately 0.020536.