a 4g of sugar C12H22O11 is dissolved in 350ml fill with hot water,what is he molarity of solution?

To find the molarity of a solution, we need to know the number of moles of solute (in this case, sugar) and the volume of the solution. Let's break down the steps to find the molarity.

Step 1: Determine the number of moles of sugar (C12H22O11).
To find the number of moles, we can use the formula:

Moles = Mass / Molar mass

Given that 4g of sugar is dissolved, the molar mass of C12H22O11 can be calculated as follows:

C = 12.01 g/mol
H = 1.01 g/mol
O = 16.00 g/mol

Molar mass of C12H22O11 = (12.01 * 12) + (1.01 * 22) + (16.00 * 11) g/mol = 342.34 g/mol

Now, we can calculate the number of moles of sugar:

Moles of C12H22O11 = 4g / 342.34 g/mol = 0.0117 moles

Step 2: Determine the volume of the solution.
The given volume is 350 mL, which needs to be converted to liters for the molarity calculation. There are 1000 mL in 1 L, so:

Volume of solution = 350 mL / 1000 = 0.35 L

Step 3: Calculate the molarity.
Molarity is defined as moles of solute divided by the volume of the solution in liters:

Molarity (M) = Moles / Volume (in liters)

Molarity = 0.0117 moles / 0.35 L ≈ 0.0334 M

Therefore, the molarity of the sugar solution is approximately 0.0334 M.

mol C12H22O11 = grams/molar mass

M = mols/L soln = mols/0.350 = ?