1-9 numbers are placed in a 3x3 box already the top right box is 1 and the bottom left croner is the number 6 figure what number is in the middle of all to make 18 in each row
8 1 6
3 5 7
4 9 2
15
To solve this problem, we need to determine the missing number in the middle of the 3x3 box to make the sum of each row equal to 18.
Let's analyze the given information:
- The top right corner is given as 1.
- The bottom left corner is given as 6.
Now, we know that the sum of each row needs to be 18. Since each row must sum up to 18, we can calculate the sum of the known numbers in both rows and subtract it from 18 to find the missing number.
First, let's calculate the sum of the known numbers in the top row:
1 (top right corner) + _ (middle number) + _ (unknown number) = 18
Since we don't know the middle number and the unknown number, we can represent them as variables:
1 + x + y = 18
Next, let's calculate the sum of the known numbers in the bottom row:
_ (unknown number) + _ (unknown number) + 6 (bottom left corner) = 18
Again, we represent the unknown numbers as variables:
z + w + 6 = 18
Now, we have two equations with four variables (x, y, z, w). To solve for the missing number, we need more information or additional equations.
Please provide more information if you have any additional clues or constraints to help narrow down the possibilities.