Math please help urgent !

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y= u+3/u-1 u=x^1/3 find dy/dx at x=8

  • Math please help urgent ! -

    dy/dx = dy/du du/dx

    du/dx = (1/3)x^-(2/3)

    dy/du = [(u-1)-(u+3)]/(u-1)^2
    = [(x^(1/3)-1)-(x^(1/3)+3)/(x^(1/3)-1)^2
    = -4 / (x^(2/3) -2x^(1/3)+1)

    so
    dy/du * du/dx
    =(-4/3)(x^-(2/3)) /(x^(2/3) -2x^(1/3)+1)
    = -4/3(x^4/3-2x +x^(2/3))

  • Math please help urgent ! -

    luckily 8^(1/3) = 2 :)

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