posted by Cynthia .
What how can I calculate the amount in moles and the mass in grams of KOH needed to convert 1.50 g of aluminum to KAl(OH)4. Balanced equation = 2 Al (s) + 2 KOH (aq) + 6 H2O (l)->2 KAl(OH)4 (aq) + 3 H2 (g)
Please show steps ..
mols Al = grams/atomic mass
Use the coefficients in the balanced equation to convert mols Al to mols KOH.
Then convert mols KOH to g. g = mols x molar mass.
All of these are done this same way with these three steps. (Sometimes the first step is mols = M x L if it is a soln. Sometimes they stick a percent yield at the end. But basically these three steps will do it.)