Chem II

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PCl5 dissociates according to the reaction: PCl5(g) ↔ PCl3(g) + Cl2(g). One mole of PCl5 was placed in one liter of solution. When equilibrium was established, 0.5 mole of PCl5 remained in the mixture. What is the equilibrium constant for this reaction?

  • Chem II -

    ............PCl5 ==> PCl3 + Cl2
    initial......1.0M......0......0
    change.......-x.......x.......x
    equil.......1-x.......x.......x

    The problem tells you that 1-x = 0.5; therefore, x = 1.0-0.5= 0.5M which means Pl3 = 0.5M and Cl2 = 0.50M

    Then K = (PCl3)(Cl2)/(PCl5) \
    Substitute and solve for K.

  • Chem II -

    thank you

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