Calculus (Area Between Curves)
posted by Mishaka .
Find the area of the region IN THE FIRST QUADRANT (upper right quadrant) bounded by the curves y=sin(x)cos(x)^2, y=2xcos(x^2) and y=4-4x.
Based on my calculations, I would say that the answer is e.) 0.37859. I am checking my answer.
That's the correct answer.
If you integrated between the end-points 0, 0.69275, 0.92811, you should have got the areas 0.28024 and 0.09835 respectively, which add up to 0.37859.
Thank you, I was just really unsure of my answer!
You're welcome! :)