Chem 1A

posted by .

Calculate the [OH ‾ ], [H+], and the pH of 0.16 M solutions of each of the following amines.
(a) triethylamine [(C2H5)3N, Kb = 4.0 10-4]
(b) hydroxylamine (HONH2, Kb = 1.1 10-8)

  • Chem 1A -

    Let's represent (C2H5O3N as B3N.
    .............B3N + HOH ==> B3NH^+ + OH^-
    initial......0.16...........0........0
    change.......-x.............x........x
    equil......0.16-x...........x........x

    Kb = (B3BH^+)(OH^-)/(B3N)
    Substitute Kb and from the ICE chart and solve for x = (OH^-). From that you can convert to pOH and to pH.
    The second one is done the same way.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Chem1C

    What is the pH of a 0.050M triethylamine, (C2H5)3N, solution?
  2. chemistry

    Calculate the cell potential of a cell operating with the following reaction at 25°C, in which [Cr2O72‾ ] = 0.030 M, [I ‾ ] = 0.020, M, [Cr3+ ] = 0.20 M, and [H+ ] = 0.60 M. Cr2O72-(aq) + 6 I ‾(aq) + 14 H+(aq) → …
  3. chemistry

    what is the oxidation half reaction, reduction half reaction, and the complete balanced reaction of the following?
  4. Chemistry

    "Arsenic acid (H3AsO4) is a triprotic acid with Ka1 = 5 10-3, Ka2 = 8 10-8, and Ka3 = 6 10-10. Calculate [H+], [OH ‾ ], [H3AsO4], [H2AsO4‾ ], [HAsO42 ‾ ], and [AsO43 ‾ ] in a 0.14 M arsenic acid solution." Okay, …
  5. Chemistry

    Calculate the [H+], [OH ‾ ], and the pH of 0.16 M solutions of: hydroxylamine (HONH2, Kb = 1.1 10-8)
  6. science

    ) A body with an initial velocity of 5ms‾¹ accelerate uniformly at the rate of 16 cm s‾² over a distance of 200 m. Calculate: (i) the acceleration in m s‾² (ii) its final velocity in m s‾¹
  7. Ap chem-Bases

    Calculate the pH of a 0.2M solution of Triethylamine, (C2H5)3N, with a Kb of 4.0x10^-4
  8. Ap chem-Bases

    Calculate the pH of a 0.2M solution of Triethylamine, (C2H5)3N, with a Kb of 4.0x10^-4
  9. Calculus III

    Compute the length of the curve r(t)=5ti+8tj+(t2+4)k over the interval 0≤t≤6 Hint: use the formula ∫t2+a2‾‾‾‾‾‾‾√dt=12tt2+a2‾‾‾‾‾‾‾√+12a2ln(t+t2+a2‾‾‾‾‾‾‾√)+C …
  10. chemistry

    5. The tetraethyl lead [Pb(C2H5)4] in a 25.00-mL sample of aviation gasoline was shaken with 15.00mL of 0.02095M I2. The reaction is: Pb(C2H5)4 + I2  Pb(C2H5)3I + C2H5I. After the reaction was complete, the unused I2 was titrated …

More Similar Questions