A sample of gas has an initial volume of 14.7L at a pressure of 1.02 atm. If the sample is compressed to a volume of 10.2L, what will its pressure be?
(P1V1)= (P2V2)
1.02 * 14.7 =14.994
14.994/10.2=1.47
To find the new pressure, we can use Boyle's law, which states that the pressure and volume of a gas are inversely proportional at a constant temperature.
Boyle's Law: P1 * V1 = P2 * V2
Where:
P1 = initial pressure,
V1 = initial volume,
P2 = final pressure,
V2 = final volume.
Given:
P1 = 1.02 atm (initial pressure),
V1 = 14.7 L (initial volume),
V2 = 10.2 L (final volume).
Applying Boyle's Law:
P1 * V1 = P2 * V2
Substituting the given values:
1.02 atm * 14.7 L = P2 * 10.2 L
Now, solve for P2:
Multiply both sides of the equation by 1/10.2 L:
(1.02 atm * 14.7 L) / 10.2 L = P2
Simplifying the equation:
P2 = 1.47 atm
Therefore, the pressure of the gas after compression to a volume of 10.2L will be 1.47 atm.
To find the final pressure of the gas sample after it has been compressed, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.
Boyle's Law formula: P1V1 = P2V2
Where:
P1 = initial pressure (1.02 atm)
V1 = initial volume (14.7 L)
P2 = final pressure (unknown)
V2 = final volume (10.2 L)
Rearranging the formula, we have:
P2 = (P1 * V1) / V2
Now, let's substitute the given values into the formula:
P2 = (1.02 atm * 14.7 L) / 10.2 L
Calculating the expression:
P2 = 14.9549 atm
Therefore, the final pressure of the gas sample, when compressed to a volume of 10.2L, will be approximately 14.95 atm.