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physics

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As part of a training schedule a weightlifter pushes a heavy metal block
along the floor. The lifter applies a force of 850 N downwards on the block
at an angle of 65° to the vertical (25° to the horizontal). The weightlifter
pushes the block forwards 4 m in 1.6 s. Calculate the power output of the
weightlifter when moving the block 4 m forwards. [10 marks]

  • physics -

    F = 850N @ 25 Deg.
    Fx = 850*cos25 = 770.4 N. = hor. Force.
    Fy = 850*sin25 = 359.2 N. = Ver. force.

    P = Fx*V = Fx * (d/t).
    P=770.4 * (4/1.6) = 1926 J/s=1926 J/s =
    1926 Watts.

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