posted by Hannah

I have to calculate the concentration of I2 produced (# of moles of I2 produced / L) based on the stoichiometric ratio in the following equation.

2S2O3^2- + I2 -> 2I^- + S4O6^2-

If you know the number of moles of S2O3^2- then the number of mols I2 will be 1/2 that. I suspect you have M and L of S2O3^- and M x L = moles S2O3^2-.

moles = M x L

M is the concentration correct?

1. Amanda Mosley

Yes m is

2. Hannah

Is L just the unit? Moles would be 3.33e-3M / L ?

3. Amanda Mosley

Yes u remember where it says mxL this means that your multiplying m by l and l would be the unit

4. Hannah

So to find the amount of I2 produced as I first posted, it would be 1/2 that of 3.33e-3 correct? So 0.0666? Sorry, its important that I understand this correct

5. Amanda Mosley

6. Hannah

So the answer would be 6.66e-2 L*min? Is that the correct unit?

7. Hannah

Sorry I actually got 0.00666 so it would be 6.6e-3 correct?

8. Hannah

So I got 6.6e-3 L*min for the amount of I2 produced. Now I have to calculate the rate for each of the 5 flasks used, so is the answer going to be the same for all 5?? It says to calculate the rate of reaction for each run using # of moles of I2 produced/L*min as the unit.

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I have to calculate the concentration of I2 produced (# of moles of I2 produced / L) based on the stoichiometric ratio in the following equation. 2S2O3^2- + I2 -> 2I^- + S4O6^2- Would the # produced be 2 for I2. I am not sure what …