PRECAL
posted by MELEK .
How can I solve this questions and get those answers????
answers
sec 13pi/4=? =>ã(2)
csc 13pi/4=? =>ã(2)
sec (pi/6)=? =>2ã(3)/3

13/4 = 3 1/4 = 2 + 1 1/4
so twice around + pi + pi/4
which is
45 degrees below x axis
cos 5 pi/4 = 1/sqrt 2 so sec 5 pi/4 = sqrt 2
the others are similar
Just remember once all the way around is 2 pi and halfway around is pi
Respond to this Question
Similar Questions

inverse trig functions
evaluate the following expressions: tan(sec^1(5/3)) tan(sec^1(25/7)) cot(csc^1(5/3)) i know the answers.. i jus don't know how to solve them =( PLEASE help me I assume your sec^1 notation denot4es the arcsecant function, etc. sec^1 … 
Confused! PreCal
Verify that each equation is an identity.. tan A= sec a/csca I have notes (i wasn't here that day and teacher refuses to reteach) but I don't understand them here is the notes... Problem w/ same directions: Cos x= cotx/csc x = Cosx/Sin … 
trig
If sinx = 3/5, tan x > 0, sec y = 13/5 and cot y < 0, find the following: a. csc(x + y) b. sec (x  y) How do I get the answers of a. 65/33 b. 65/16 Thank you 
Pre Calculus.
Can someone check my answers please!!! Simplify (tan ^2 theta csc^2 theta1)/(tan^2 theta). My answer: 1 Simplify ((cos x)/(sec x1)) + ((cos x) /(sec x +1) My answer: 2cot^2 x Find a numerical value of one trigonometric function of … 
Pre Cal
Vertify the identities, clearly show each step (vertify one side that they are equal to each other) sec^2+csc^2=sec^2+csc^2 
Pre Cal
Vertify the identities, clearly show each step (vertify one side that they are equal to each other) sec^2+csc^2=sec^2+csc^2 
pre cal
can someone please show me how to verify this identity? 
Math
Given that cos 13pi/18=sin y, first express 13pi/18 as a sum of pi/2 and an angle, and then apply a trigonometric identitiy to determine the measure of angle y. 
Pre cal
Sec^2x=2 With 10 different answers 
Trig verifying identities
I am having trouble with this problem. sec^2(pi/2x)1= cot ^2x I got : By cofunction identity sec(90 degrees  x) = csc x secx csc1 = cot^2x Then split sec x and csc1 into two fractions and multiplied both numerator and denominators …