Use Lagrange multipliers to find the max/min values of the function f(x,y)=xy subject to the constraint: x^2/8+y^2/2 =1
Pleasssse help me with this!!
Set up the objective function, F(x,y,L)
(L stands for lambda) such that
F(x,y,L)=xy+L(x^2/8+y^2/2-1)
Now calculate and equate to zero the partial derivatives with respect to each of the independent variables, x, y and L.
∂F/∂x = y + xL/4 =0
∂F/∂y = x + yL =0
∂F/∂L = x²/8+y²/2-1=0
Solve for x, y and L and check if it is a maximum or minimum.